I was looking at the eq protocol information and I was curious if anyone knows how to decrypt this. The part in question is the 24byte password hash. Thanks in advance:
Header Data:
dwSEQ - 0x0001: This is seqence number 0x0001 from the client.
Upon receiving, ignore any further packets <= dwSEQ.
dwARSP - 0x339a: Response to ARQ 0x339a.
dwARQ - 0x09be: Use this for responding.
ASQ_high - 0x01: Not sure.
ASQ_low - 0x01: Not sure.
dwOpCode - 0x0100: Send Login Info.
CRC32 - 0xe4a6e1e2: CRC Check.
Data:
The first thing sent is a null terminated username ("Fizban1" in this case).
After that, a 24-byte password hash is sent. The rest of the packet
doesn't seem to change between logins (not sure what 'none' is for).
I am assuming this means you cannot help me? Is it possible to provide any hints for this or am I going to have to research it on my own?
PS. If its any consellation, I'm using very old version of the client, kunark release. So it wont interfere with what EqEmu is doing. And from my understanding the encryption has changed since then.
I understand not wanting to distribute it. I was just curious if anyone would be able to provide some information or tips about how I can go about this with what I am assuming is a very old protocol used.
Well anything that anyone could provide you would have to be outside these forums. We have an agreement with the folks that created it that we would not contribute to its getting out. And that agreement goes back a LONG way so we are really not able to help you publicly.
We aren't trying to jerk you around freezzo. The circumvention of the client encryption is on the top end of the DMCA danger scale right along with publishing the box art as your own and is thus considered illegal in most forms on these forums, as Andrew is pointing out.
No problem guys. I appreciate you taking the time. I just wasn't sure where to ask such information and I do not want to cause legal issues with it, so I will drop it here.
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