Junior Developer Code

[maaltan]

a very simple calculator, im just typing it in here so you might have to correct some small compile errors, but the logic should be sound.
That would make a good debugging exercise for the trainees

I tried leaving pointers out of it .. but hell thats what c runs on you have to learn them eventually.

You will have to break out though its infinate

#include <stdio.h>

int main()
{
 float oprand; 
    float accumulator; 
    char buf=' ';

while (1) 
{ 
   printf("Enter a the first number\n"); 
   scanf("%f", &accumulator); 
   buf = ' ';
while (buf != '=') 
{
   
   printf("Enter +,-,*, /   Or enter = to get result\n");
   scanf("%s", &buf);

   if (buf != '=')
   {
	   printf("Enter next number.\n");
	   scanf("%f", &oprand);
   }

   switch (buf)
   {
        case '+':
               accumulator+=oprand;
			   break;
        case '-':
               accumulator-=oprand;
			   break;
        case '*':
               accumulator*=oprand;
			   break;
        case '/':
               accumulator/=oprand;
			   break;
        case '=':
                printf("Result: %f\n", accumulator);
				break;
        default:
            printf("invalid operator\n"); // have to have it to prevent the program from crashing, you may wish to put debugging info in here
    }

}
}

} // err lost track of braces this might not be needed

well its started out simple .. hope it helps actually it turned out to be c instead of c++ .. eeh it will work in c++ .. replace the printfs and scanfs with cin and cout stream redirections like your use to ..then it be c++