Password encryption information?

[freezzo]

I was looking at the eq protocol information and I was curious if anyone knows how to decrypt this. The part in question is the 24byte password hash. Thanks in advance:

(3) Client sends login info.
23:57:05.842104 client.1538 > server.10002: 61
0x0000 1204 0001 339a 09be 0101 0100 4669 7a62 ....3..$....Fizb
0x0010 616e 3100 1db5 28f1 02a5 cde2 a513 23da an1...X2..b.V..!
0x0020 19d5 5dae b12d e6af e53b ed50 6e6f 6e65 ...O.,...e..none
0x0030 0000 0000 0000 0000 00e4 a6e1 e2 ...........m.

Flags set:
ASQ - Not sure.
ARQ - ACK Request.
ARSP - ACK Response.

Header Data:
dwSEQ - 0x0001: This is seqence number 0x0001 from the client.
Upon receiving, ignore any further packets <= dwSEQ.
dwARSP - 0x339a: Response to ARQ 0x339a.
dwARQ - 0x09be: Use this for responding.
ASQ_high - 0x01: Not sure.
ASQ_low - 0x01: Not sure.
dwOpCode - 0x0100: Send Login Info.
CRC32 - 0xe4a6e1e2: CRC Check.

Data:
The first thing sent is a null terminated username ("Fizban1" in this case).
After that, a 24-byte password hash is sent. The rest of the packet
doesn't seem to change between logins (not sure what 'none' is for).